logo
Find the square

Find the square

Hindustan Times9 hours ago

I learnt something new and interesting recently. Most puzzle solvers, including you readers of Problematics, probably know this already, but here it is anyway. To check if a number is a perfect square, one way to proceed is to keep adding its digits until you reach a single digit. If it's a square, the ultimate 'digital root' in a single digit must be any one of 1, 4, 7 and 9 — and nothing else. Welcome to Problematics!(Shutterstock)
For example, the digital root of 16 is 1 + 6 = 7, that of 81 is 8 + 1 = 9, that of 49 is 4 + 9 = 13 followed by 1 + 3 = 4, and that of 676 is 6 + 7 + 6 = 19 followed by 1 + 9 = 10 and finally 1. There are, of course, numbers that can have digital roots of 1, 4, 7 or 9 without being perfect squares, for example 70 whose root is 7. So the method may not always tell you if a number is a perfect square, but it will definitely help you rule out many possibilities.
#Puzzle 148.1
A century ago, the English puzzler Henry Ernest Dudeney presented six numbers to his readers:
4784887 2494651 8595087 1385287 9042451 9406087
Three of them can be added to form a perfect square, Dudeney wrote, inviting his readers to identify them.
I managed to find the three numbers using hit and trial, paired with some observations that eliminated one or more possibilities. Then I looked at Dudeney's solution and learnt about digital roots and how the rule could be applied to solve this puzzle. Who knows, there may be other methods too. Use any method — hit and trial, digital roots, or any procedure you may innovate yourself. But do send me the three numbers that satisfy the condition.
#Puzzle 148.2
The Village of Music is organising a concert and has invited a musician from the Village of Astronomy. The Village of Astronomy, on the other hand, is inaugurating a telescope and has invited an astronomer from the Village of Music. By sheer coincidence, both events begin at the same time on the same day.
The musician from Astronomy, who wants to get some exercise, decides to walk the whole distance and sets off towards Music at 12 noon on the day of the event. The astronomer from Music chooses to cycle the distance and sets off towards Astronomy at 2pm. Both are good puzzlers and can manage their respective speeds precisely. Indeed, each one arrives at his destination at the exact moment that his event starts.
This is after the two had met on the way, which happened at 4:05pm. They called out 'HI!' to each other but neither stopped. At what time do the two events start?
MAILBOX: LAST WEEK'S SOLVERS
#Puzzle 147.1 HT picture
Hi Kabir,
Based on the conditions that surnames and addresses do not begin with the same letter, and that of four statements only one is true, we can map different scenarios as shown in the table. Statement 1 is not possible. From the other three statements, whichever one is true, only one address can be established for sure, i.e the Poonawala family lives in Surat.
— Sabornee Jana, Mumbai
***
Hi,
The only address that can be definitely established is that the Poonawala family is from Surat. Statement (1) must be false. Statements (2), (3) and (4) give different combinations that do not violate the given conditions. Therefore any two of them can be false. But no matter which one statement is true, one address is common to each combination — the Poonawala family must live in Surat.
— Ajay Ashok, Delhi
#Puzzle 147.2
Hi Kabir,
Each of the ten statements contradicts every other statement. Therefore, at the most one can be true. That is, either exactly one statement is true (this is what statement 9 is) or none of them is true (this is what statement 10 is). However, statement 10 contradicts itself. Therefore, only statement 9 is true and the remaining nine are false.
— Professor Anshul Kumar, Delhi
Solved both puzzles: Sabornee Jana (Mumbai), Ajay Ashok (Delhi), Professor Anshul Kumar (Delhi), Dr Sunita Gupta (Delhi), Yadvendra Somra (Sonipat), Vinod Mahajan (Delhi), Abhinav Mital (Singapore), Shri Ram Aggarwal (Delhi)
Solved Puzzle 147.2: Kanwarjit Singh (Chief Commissioner of Income-tax, retired), Dr Vivek Jain (Baroda) Problematics will be back next week. Please send in your replies by Friday noon to problematics@hindustantimes.com

Orange background

Try Our AI Features

Explore what Daily8 AI can do for you:

Comments

No comments yet...

Related Articles

CSIR UGC NET June 2025: Registration ends today, check details here
CSIR UGC NET June 2025: Registration ends today, check details here

Hindustan Times

time2 hours ago

  • Hindustan Times

CSIR UGC NET June 2025: Registration ends today, check details here

The National Testing Agency (NTA) will close the registration process for CSIR UGC NET June 2025 today, June 23, 2025. Candidates who want to register for CSIR UGC NET 2025 can apply at CSIR UGC NET June 2025: Registration ends today (Representational image)(Unsplash) With this, the last date for payment is tomorrow, June 24, 2025. The date for CSIR UGC NET examination is July 26 to 28, 2025. The exam will be held in bilingual, i.e. Hindi and English. Candidates will have to attempt as per the option exercised in the application Form. Moreover, in case of any ambiguity, the English version would be treated as final. The examination is scheduled to be conducted in Computer-Based Test (CBT) mode. The Test will consist of three parts, with objective-type, multiple-choice questions (MCQs), and no break between papers will be provided. Also read: JEECUP Polytechnic result 2025 live updates Here are the steps to apply:- Visit the official website at On the home page, click on the registration link of 'CSIR UGC NET June 2025'. Enter your registration details. Submit and log in to the account. Fill the application form and pay the fees via online mode. Submit the form and download it for further use. As notified by the official notice, candidates can only submit one application. If any candidates fill out more than one application form, strict action will be taken against them. For more such details, candidates are advised to visit the official website.

Karnataka PGCET 2025 Answer Key To Be Out Soon; Check Steps To Download
Karnataka PGCET 2025 Answer Key To Be Out Soon; Check Steps To Download

NDTV

time4 hours ago

  • NDTV

Karnataka PGCET 2025 Answer Key To Be Out Soon; Check Steps To Download

Karnataka PGCET Answer Key 2025: The Karnataka Examinations Authority (KEA) is expected to release the official answer key for the Karnataka Post Graduate Common Entrance Test (PGCET) 2025 soon. Candidates who appeared for the examination will be able to download the answer key from the official website — The PGCET 2025 exam was conducted on June 22, 2025, for both MBA and MCA programs. Karnataka PGCET 2025 Answer Key: Steps To Download Step 1. Visit the official website: Step 2. On the homepage, click on 'Karnataka PGCET 2025 Answer Key' Step 3. A new page will appear on the screen Step 4. Check and download the answer key Step 5. Take a printout of the answer key for future reference Karnataka PGCET 2025: Exam Pattern The Karnataka Post Graduate Common Entrance Test (PGCET) 2025 is conducted to determine eligibility for admission into MBA, MCA, ME, MTech, and courses offered by various institutions in Karnataka. The exam is a Computer-Based Test (CBT) conducted in English, with a duration of 120 minutes. It consists of 100 multiple-choice questions (MCQs), carrying a total of 100 marks. Candidates are awarded 1 mark for each correct answer, and there is no negative marking. The question paper is divided into four sections, each with four answer options. Karnataka PGCET 2025: Post-Result Process Candidates who qualify in the exam and are shortlisted for counselling must report to their designated colleges for document verification and admission formalities. It is mandatory to carry all original documents, along with self-attested photocopies, during the verification process.

UGC NET June 2025 admit card released; here's download link
UGC NET June 2025 admit card released; here's download link

Scroll.in

time4 hours ago

  • Scroll.in

UGC NET June 2025 admit card released; here's download link

The National Testing Agency (NTA) has released the admit cards of the University Grants Commission National Eligibility Test June 2025 or UGC NET June 2025. Eligible candidates can download their hall tickets from the official website The computer-based test will be conducted from June 25 to 29, 2025. The test paper will consist of two sections: Paper I (50 questions of 100 marks) and Paper II (100 questions of 200 marks). There will be no break between the papers. Each question carries two marks, and there's no negative marking for incorrect answers. The Paper will be bilingual i.e., in English and Hindi only, except language papers. 'In case any candidate faces difficulty in downloading the Admit Card or discrepancy in the details contained in the Admit Card, candidates for UGC – NET June 2025, he/she can contact on 011- 40759000 or e – mail at ugcnet@ reads the notification. Steps to download UGC NET June 2025 admit card

DOWNLOAD THE APP

Get Started Now: Download the App

Ready to dive into a world of global content with local flavor? Download Daily8 app today from your preferred app store and start exploring.
app-storeplay-store