Latest news with #JointCSIR-UGCNationalEligibilityTest
India.com
02-08-2025
- General
- India.com
UGC-CSIR NET Answer Key 2025 out at csirnet.nta.ac.in; check details, last date to raise objections
UGC NET Result 2025 big update: NTA UGC NET Result to be declared on....; know how to check scores at The provisional answer key for the Joint CSIR-UGC National Eligibility Test (CSIR NET) 2025 has been released by the National Testing Agency (NTA). Candidates who have appeared for the June session exam, can now access the answer key and their individual response sheets through the official website at A total of 1,95,241 candidates gave this exam, on 28th July. The CSIR NET June 2025 session was held to determine eligibility for the Junior Research Fellowship (JRF), appointment as assistant professor and admission to PhD programs in universities and institutions across India. How to raise challenge in CSIR NET June 2025 Answer Key? Candidates can follow the steps provided below in order to challenge the answer key: Go to the official NTA CSIR NET website at Select the 'Challenge Answer Key' link and log in using your application number, date of birth, and security pin. Once you log in, select 'View Answer Sheet' to see your marked responses. If you want to raise an objection. Click on the 'Challenge' button. Enter the question ID and the correct answer as per the provisional answer key. Upload the supporting documents. Review your challenge. You can use the 'Modify Claim' option if needed. You would be required to pay an objection fee of Rs 200 per question to complete the process, and submit. The deadline to raise objections is August 3, and the objection fee is non-refundable. Only the challenges which are submitted with valid payment and documentation will be considered.
Indian Express
01-08-2025
- General
- Indian Express
UGC-CSIR NET Answer Key 2025 out at csirnet.nta.ac.in, raise objections by August 3
The National Testing Agency (NTA) has released the provisional answer key for the Joint CSIR-UGC National Eligibility Test (CSIR NET) 2025. Candidates who appeared for the June session exam can access the answer key and their individual response sheets through the official website at The exam was conducted on July 28 for a total of 1,95,241 candidates. The CSIR NET June 2025 session was held for eligibility determination for the Junior Research Fellowship (JRF), appointment as assistant professor, and admission to PhD programmes in universities and institutions across the country. Candidates can challenge the provisional answer key by following the steps below: Step 1: Visit the official NTA CSIR NET website at Step 2: Click on the 'Challenge Answer Key' link and log in using your application number, date of birth, and security pin. Step 3: After logging in, click on 'View Answer Sheet' to see your marked responses. Step 4: To raise an objection, click on the 'Challenge' button. Step 5: Enter the question ID and the correct answer as per the provisional answer key. Step 6: Upload relevant supporting documents. Step 7: Review your challenge. You may use the 'Modify Claim' option if needed. Step 8: Pay the objection fee of Rs 200 per question to complete the process, and submit. The last date to raise objections is August 3. The objection fee is non-refundable, and only challenges submitted with valid payment and documentation will be considered.
